U Whole numbers 1 to 10 A 2357 B 246810 C 13579 D 149 1 AB 2 BC 3 AC 4 CD 5 A 6 B 7 AC BD 8 AB 9 UA 10 CD 11 AB C AC 12 C AD AB C 13 C AD 14 A BC 15 AB CD
Question
Basic Answer
Step 1: A ∪ B
Union of sets A and B:
A ∪ B = {2, 3, 4, 5, 6, 7, 8, 10}
Step 2: B ∪ C
Union of sets B and C:
B ∪ C = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
Step 3: A ∩ C
Intersection of sets A and C:
A ∩ C = {3, 5, 7}
Step 4: C ∩ D
Intersection of sets C and D:
C ∩ D = {1, 9}
Step 5: A’
Complement of set A in U:
A’ = U – A = {1, 4, 6, 8, 9, 10}
Step 6: B’
Complement of set B in U:
B’ = U – B = {1, 3, 5, 7, 9}
Step 7: (A ∪ C) ∩ (B ∪ D)
Union of A and C, then intersection with union of B and D:
A ∪ C = {1, 2, 3, 5, 7, 9}
B ∪ D = {1, 2, 4, 6, 8, 9, 10}
(A ∪ C) ∩ (B ∪ D) = {1, 2, 9}
Step 8: A – B
Difference of sets A and B:
A – B = {3, 5, 7}
Step 9: U – A
Complement of set A in U:
U – A = {1, 4, 6, 8, 9, 10}
Step 10: C – D
Difference of sets C and D:
C – D = {3, 5, 7}
Step 11: (A – B) ∩ C
Difference of A and B, then intersection with C:
A – B = {3, 5, 7}
(A – B) ∩ C = {3, 5, 7}
Step 12: C’ ∩ (A ∪ D)
Complement of C, then intersection with union of A and D:
C’ = {2, 4, 6, 8, 10}
A ∪ D = {1, 2, 3, 4, 5, 7, 9}
C’ ∩ (A ∪ D) = {2, 4}
Step 13: C’ ∩ (A ∪ D)
Complement of C, then intersection with union of A and D:
C’ = {2, 4, 6, 8, 10}
A ∪ D = {1, 2, 3, 4, 5, 7, 9}
C’ ∩ (A ∪ D) = {2, 4}
Step 14: A ∪ (B ∪ C)’
Union of A with complement of union of B and C:
B ∪ C = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
(B ∪ C)’ = {}
A ∪ (B ∪ C)’ = {2, 3, 5, 7}
Step 15: (A ∪ B) ∩ (C ∪ D)
Union of A and B, then intersection with union of C and D:
A ∪ B = {2, 3, 4, 5, 6, 7, 8, 10}
C ∪ D = {1, 3, 4, 5, 7, 9}
(A ∪ B) ∩ (C ∪ D) = {3, 4, 5, 7}
Final Answer
- A ∪ B = {2, 3, 4, 5, 6, 7, 8, 10}
- B ∪ C = {1, 2, 3, 4, 5, 6, 7, 8, 9, 10}
- A ∩ C = {3, 5, 7}
- C ∩ D = {1, 9}
- A’ = {1, 4, 6, 8, 9, 10}
- B’ = {1, 3, 5, 7, 9}
- (A ∪ C) ∩ (B ∪ D) = {1, 2, 9}
- A – B = {3, 5, 7}
- U – A = {1, 4, 6, 8, 9, 10}
- C – D = {3, 5, 7}
- (A – B) ∩ C = {3, 5, 7}
- C’ ∩ (A ∪ D) = {2, 4}
- C’ ∩ (A ∪ D) = {2, 4}
- A ∪ (B ∪ C)’ = {2, 3, 5, 7}
- (A ∪ B) ∩ (C ∪ D) = {3, 4, 5, 7}
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