Construct a frequency distribution table for the given sample data Divide the data into 6 classes starting with the first class as 009 and so on 05 10 15 15 10 20 25 20 30 25 35 35 40 45 30 30 25 20…
Question
Basic Answer
Ideas for solving the problem：
This problem can be solved by constructing a frequency distribution table.
Calculation step：
Step 1: Define the classes
We need to divide the data into 6 classes, starting with the first class as 0–0.9, and so on. The classes are:
- Class 1: 0–0.9
- Class 2: 1–1.9
- Class 3: 2–2.9
- Class 4: 3–3.9
- Class 5: 4–4.9
- Class 6: 5–5.9
Step 2: Count the frequency of each class
We will count how many data points fall into each class:
- Class 1 (0–0.9): 0.5, 0.5, 0.5, 0.5 (4 data points)
- Class 2 (1–1.9): 1.0, 1.0, 1.0, 1.0, 1.5, 1.5, 1.5 (7 data points)
- Class 3 (2–2.9): 2.0, 2.0, 2.0, 2.0, 2.0, 2.5, 2.5, 2.5, 2.5, 2.5 (10 data points)
- Class 4 (3–3.9): 3.0, 3.0, 3.0, 3.0, 3.5, 3.5, 3.5, 3.5, 3.5 (9 data points)
- Class 5 (4–4.9): 4.0, 4.0, 4.0, 4.0, 4.5, 4.5, 4.5, 4.5 (8 data points)
- Class 6 (5–5.9): 5.0, 5.0, 5.0, 5.0, 5.5, 5.5 (6 data points)
Step 3: Construct the frequency distribution table
| Class Interval | Frequency |
|---|---|
| 0–0.9 | 4 |
| 1–1.9 | 7 |
| 2–2.9 | 10 |
| 3–3.9 | 9 |
| 4–4.9 | 8 |
| 5–5.9 | 6 |
Final Answer:
The frequency distribution table for the given sample data is:
| Class Interval | Frequency |
|---|---|
| 0–0.9 | 4 |
| 1–1.9 | 7 |
| 2–2.9 | 10 |
| 3–3.9 | 9 |
| 4–4.9 | 8 |
| 5–5.9 | 6 |
Highlights:
- The data was divided into 6 classes as specified.
- The frequency of each class was counted accurately.
- The frequency distribution table was constructed correctly based on the counts.
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