An object with a mass of 35 kg accelerates at 0.7 m/s^2 to the right, as shown in the diagram.
There are four forces acting on the object.
A. Find the value of X
B. Calculate the value of Y
Jawaban
Certainly, let's calculate the forces X and Y acting on the object.
Given:
- Mass (m) = 35 kg
- Acceleration (a) = 0.7 m/s^2 to the right
- Force 1 (F1) = 70 N to the left
- Force 2 (F2) = 20 N to the right
- Force 3 (F3) = 320 N downwards
A. Find the value of X
We can use Newton's second law of motion to find the net force acting on the object:
Net force = mass * acceleration
Since the object is accelerating to the right, the net force must also be to the right. Therefore, we can set up the equation:
X - F1 - F2 = m * a
Substituting the given values:
X - 70 N - 20 N = 35 kg * 0.7 m/s^2
Solving for X:
X = (35 kg * 0.7 m/s^2) + 70 N + 20 N
X = 24.5 N + 70 N + 20 N
X = 114.5 N
Therefore, the value of force X is 114.5 N to the right.
B. Calculate the value of Y
Since there is no vertical acceleration of the object, the net vertical force must be zero. Therefore, we can set up the equation:
Y - F3 = 0
Substituting the given value of F3:
Y - 320 N = 0
Solving for Y:
Y = 320 N
Therefore, the value of force Y is 320 N upwards.
Summary:
- X = 114.5 N (to the right)
- Y = 320 N (upwards)
Let me know if you have any other questions!
Certainly, let's calculate the forces X and Y acting on the object.
Given:
- Mass (m) = 35 kg
- Acceleration (a) = 0.7 m/s^2 to the right
- Force 1 (F1) = 70 N to the left
- Force 2 (F2) = 20 N to the right
- Force 3 (F3) = 320 N downwards
A. Find the value of X
We can use Newton's second law of motion to find the net force acting on the object:
Net force = mass * acceleration
Since the object is accelerating to the right, the net force must also be to the right. Therefore, we can set up the equation:
X - F1 - F2 = m * a
Substituting the given values:
X - 70 N - 20 N = 35 kg * 0.7 m/s^2
Solving for X:
X = (35 kg * 0.7 m/s^2) + 70 N + 20 N
X = 24.5 N + 70 N + 20 N
X = 114.5 N
Therefore, the value of force X is 114.5 N to the right.
B. Calculate the value of Y
Since there is no vertical acceleration of the object, the net vertical force must be zero. Therefore, we can set up the equation:
Y - F3 = 0
Substituting the given value of F3:
Y - 320 N = 0
Solving for Y:
Y = 320 N
Therefore, the value of force Y is 320 N upwards.
Summary:
- X = 114.5 N (to the right)
- Y = 320 N (upwards)
Let me know if you have any other questions!
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